Binomial Distribution on TI-84 and Desmos

Binomial probability questions ask for “exactly”, “at most”, “at least” or “between”. Each one maps to a specific calculator command, and the “at least” case is where most mistakes happen. This guide covers the TI-84 and the Desmos calculator in Bluebook, with one worked example you can follow on either.

Quick answer: binompdf is for exactly k. binomcdf adds up everything from 0 to k, so it is at most k. For at least k, use 1 minus the cdf at k − 1.

First: is it really binomial? (BINS)

The commands

You needTI-84 (DISTR = 2nd VARS)Desmos
Exactly kbinompdf(n, p, k)binomialdist(n,p).pdf(k)
At most k (≤)binomcdf(n, p, k)binomialdist(n,p).cdf(k)
Fewer than k (<)binomcdf(n, p, k−1)binomialdist(n,p).cdf(k-1)
At least k (≥)1 − binomcdf(n, p, k−1)1-binomialdist(n,p).cdf(k-1)
More than k (>)1 − binomcdf(n, p, k)1-binomialdist(n,p).cdf(k)
Between a and b, inclusivebinomcdf(n, p, b) − binomcdf(n, p, a−1)binomialdist(n,p).cdf(a,b)

Worked example: free throws

A player makes 60% of free throws and takes 20 shots. Let X be the number made, so X is binomial with n = 20 and p = 0.6.

QuestionCalculator inputAnswer
Exactly 12 madebinomialdist(20,0.6).pdf(12) or binompdf(20, 0.6, 12)0.1797
At most 9 madebinomialdist(20,0.6).cdf(9) or binomcdf(20, 0.6, 9)0.1275
At least 15 made1-binomialdist(20,0.6).cdf(14) or 1 − binomcdf(20, 0.6, 14)0.1256
Between 10 and 14 madebinomialdist(20,0.6).cdf(10,14)0.7469

The expected number made is μ = np = 20(0.6) = 12, and the standard deviation is σ = √(np(1−p)) = √(20 × 0.6 × 0.4) = 2.19.

Check the exactly-12 answer by hand with P(X = k) = C(n, k) pk(1 − p)n−k: C(20, 12) = 125,970, so P(X = 12) = 125,970 × 0.612 × 0.48 = 0.1797. The combinations calculator will find the C(20, 12) part for you.

Translate the words into a symbol

Whenever the question says “at least” or “more than”, you are using the complement: everything except the values you don’t want. That is why the cdf is evaluated one step below k for “at least”.

What to write on the free-response section

Define the variable, name the distribution with its parameters, and show the calculation with labels. For the “at least 15” question:

“Let X = the number of free throws made in 20 attempts. X is binomial with n = 20 and p = 0.6. P(X ≥ 15) = 1 − P(X ≤ 14) = 1 − binomcdf(20, 0.6, 14) = 0.1256.”

The 2026 scoring guidelines accepted labeled Desmos syntax in the same way, such as binomialdist(n = 10, p = 0.2459) for a different problem, alongside TI notation. A bare number with no setup is not enough.

Common mistakes

Everything else in this unit is in the Unit 2 study guide. The same calculators and the rest of the procedures are in the AP Stats calculator guide and the one-page cheat sheet.

Desmos syntax tested in the College Board practice calculator and checked against independent statistical software. Updated for the May 2027 exam. Last reviewed October 2026.

Frequently Asked Questions

  1. How do I calculate a binomial probability on a TI-84?

    Press 2nd then VARS to open the DISTR menu. Choose binompdf for the probability of exactly k successes, entering n, p and k, or choose binomcdf for the probability of k or fewer successes, entering n, p and k.

  2. How do I find "at least" in a binomial problem on Desmos?

    Use the complement. For at least k successes, type 1-binomialdist(n,p).cdf(k-1). For example, the probability of at least 15 successes in 20 trials with p = 0.6 is 1-binomialdist(20,0.6).cdf(14), which is about 0.1256.

  3. What is the difference between binompdf and binomcdf?

    The pdf gives the probability of exactly k successes. The cdf is cumulative: it gives the probability of k or fewer successes by adding the probabilities for 0 through k. In Desmos these are the .pdf and .cdf properties of binomialdist.

  4. When can I use the binomial distribution?

    When each trial has two outcomes, the trials are independent, the number of trials is fixed, and the probability of success is the same each time. When sampling without replacement, the sample should be no more than 10% of the population so independence is a reasonable assumption.

Sources

← Browse all free math calculators